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56 questions at your level, grouped by concept

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  1. 1
    A pump raises 200 kg200\text{ kg} of water through a vertical height of 15 m15\text{ m} and ejects it with speed 6 m s−16\text{ m s}^{-1}. Take g=10 m s−2g = 10\text{ m s}^{-2}.

    Find the total work done by the pump. (5 marks)
    Level 5 · 5 marksTry it
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  1. 1
    A skier of mass 70 kg70\text{ kg} starts from rest and descends a run whose end is 40 m40\text{ m} below its start. The total work done against resistive forces during the run is 16 000 J16\,000\text{ J}. Take g=10 m s−2g = 10\text{ m s}^{-2}.

    Find the skier's speed at the end of the run, giving your answer to 33 significant figures. (5 marks)
    Level 5 · 5 marksTry it

Power

22 questions

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  1. 1
    A tractor of mass 35003500 kg is used on a farm.

    The tractor is moving along a straight horizontal track with its engine working at a constant rate of 2424 kW. The resistance to the motion of the tractor is modelled as a constant force of magnitude RR newtons. When the tractor is moving at 6 m s−16\ \text{m s}^{-1}, its acceleration is 0.8 m s−20.8\ \text{m s}^{-2}
    (a) Using the model, show that R=1200R = 1200

    (4 marks)

    The tractor is then driven along a different track, from a point AA in the farmyard to a point BB at the gate of a field. The track from AA to BB is 450450 m long and BB is 1818 m higher than AA. The tractor passes AA with speed 2 m s−12\ \text{m s}^{-1} and passes BB with speed 5 m s−15\ \text{m s}^{-1}

    The resistance to the motion of the tractor from non-gravitational forces is modelled as a constant force of magnitude 12001200 N.
    (b) Find the total work done by the engine of the tractor as the tractor moves from AA to BB.

    (5 marks)

    Later, the tractor climbs a straight hill which is inclined to the horizontal at an angle β\beta, where sin⁡β=112\sin\beta = \frac{1}{12}. The engine is working at a constant rate of 1515 kW and the tractor moves up the hill at a constant speed of V m s−1V\ \text{m s}^{-1}. The resistance to the motion of the tractor from non-gravitational forces is again modelled as a constant force of magnitude 12001200 N.
    (c) Find the value of VV.

    (4 marks)
    Level 5 · 13 marksTry it
  2. 2
    A lorry of mass 60006000 kg is moving up a straight hill which is inclined to the horizontal at an angle α\alpha, where sin⁡α=135\sin\alpha = \frac{1}{35}. The engine of the lorry is working at a constant rate of 3636 kW and the lorry is moving at a constant speed of 15 m s−115\ \text{m s}^{-1}. The resistance to the motion of the lorry from non-gravitational forces is modelled as a constant force of magnitude RR newtons.
    (a) Show that R=720R = 720

    (4 marks)

    On another day, the lorry is towing a trailer of mass 20002000 kg along a straight horizontal road, as shown in Figure 1.

    Figure 12000 kg6000 kgDiagram not accurately drawn.

    The trailer is attached to the lorry by a towbar which is parallel to the road. The towbar is modelled as a light rod. The resistance to the motion of the lorry is 720720 N and the resistance to the motion of the trailer is 400400 N. The engine of the lorry is again working at a constant rate of 3636 kW.
    (b) Find the acceleration of the lorry at the instant when its speed is 10 m s−110\ \text{m s}^{-1}

    (4 marks)
    (c) Find the tension in the towbar at this instant.

    (3 marks)

    Later, the lorry tows the trailer up the hill described in part (a). At the instant when the lorry and the trailer are moving up the hill at 9 m s−19\ \text{m s}^{-1}, the towbar breaks. The resistance to the motion of the trailer from non-gravitational forces is still 400400 N.
    (d) Use the work–energy principle to find how far the trailer travels up the hill between the towbar breaking and the trailer coming to instantaneous rest.

    (4 marks)
    Level 5 · 15 marksTry it
  3. 3
    A lorry of mass 5000 kg5000\text{ kg} moves along a level road. Its engine works at a constant rate of 60 kW60\text{ kW}, and the total resistance to motion is constant at 1500 N1500\text{ N}.
    (a) Find the maximum speed of the lorry on the level road. (3 marks)
    (b) Find the acceleration of the lorry at the instant when its speed is 20 m s−120\text{ m s}^{-1}. (3 marks)
    Level 5 · 6 marksTry it

All 22 power questions