Browse Work, energy & power

56 questions at your level, grouped by concept

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  1. 1
    Figure 1θABDiagram not accurately drawn.

    A straight plank is fixed with its lower end on horizontal ground and its upper end on top of a vertical wall. The plank is inclined to the horizontal at an angle θ\theta, where tan⁡θ=512\tan\theta = \frac{5}{12}, and the upper surface of the plank is rough.

    A small block of mass 33 kg is projected up the plank from the point AA with speed U m s−1U\ \text{m s}^{-1}. The block slides along a line of greatest slope of the plank and comes to instantaneous rest at the point BB, as shown in Figure 1. The point BB is 1.51.5 m vertically above AA.

    The coefficient of friction between the block and the plank is 14\frac{1}{4}

    The block is modelled as a particle.
    (a) Find the work done by the block against friction as it travels from AA to BB.

    (3 marks)
    (b) Use the work–energy principle to find the value of UU.

    (4 marks)

    The block then slides back down the plank.
    (c) Use the work–energy principle to find the speed with which the block passes back through AA.

    (3 marks)
    Level 4 · 10 marksTry it
  2. 2
    A small ring PP of mass mm is threaded on a fixed rough straight wire. The wire lies in a vertical plane and is inclined to the horizontal at an angle α\alpha, where tan⁡α=815\tan\alpha = \frac{8}{15}

    The coefficient of friction between PP and the wire is 13\frac{1}{3}

    The ring is modelled as a particle.
    (a) Show that, while PP is moving along the wire, the magnitude of the frictional force acting on PP is 517mg\frac{5}{17}mg

    (2 marks)

    The points AA and BB lie on the wire, with BB higher than AA and AB=17aAB = 17a, where aa is a positive constant. The ring is projected up the wire from AA and first comes to instantaneous rest at BB.
    (b) Use the work–energy principle to find, in terms of aa and gg, the speed with which PP is projected from AA.

    (4 marks)

    The ring then slides back down the wire towards AA.
    (c) Use the work–energy principle to find, in terms of aa and gg, the speed with which PP passes back through AA.

    (4 marks)
    Level 4 · 10 marksTry it
  3. 3
    A block of mass 2 kg2\text{ kg} is released from rest and slides 5 m5\text{ m} down the line of greatest slope of a rough plane inclined at angle θ\theta, where sin⁡θ=0.6\sin\theta = 0.6. It reaches the bottom moving at 5 m s−15\text{ m s}^{-1}. Take g=10 m s−2g = 10\text{ m s}^{-2}.
    (a) Find the potential energy lost. (2 marks)
    (b) Find the kinetic energy gained. (1 mark)
    (c) Hence find the work done against friction. (2 marks)
    Level 4 · 5 marksTry it

All 19 work done by a force questions

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  1. 1
    A child of mass 30 kg30\text{ kg} starts from rest at the top of a smooth curved slide and descends a vertical height of 5 m5\text{ m}. Taking g=10 m s−2g = 10\text{ m s}^{-2}:
    (a) Find the child's speed at the bottom of the slide. (3 marks)
    (b) Find the child's kinetic energy at the bottom. (2 marks)5 mv = ?
    Level 4 · 5 marksTry it
  2. 2
    A block of mass 3 kg3\text{ kg} is projected with speed 8 m s−18\text{ m s}^{-1} along a rough horizontal surface. A constant frictional force brings it to rest after a distance of 4 m4\text{ m}.
    (a) Find the initial kinetic energy of the block. (2 marks)
    (b) State the work done against friction. (1 mark)
    (c) Hence find the magnitude of the frictional force. (2 marks)
    Level 4 · 5 marksTry it
  3. 3
    A stone is thrown from ground level with speed 15 m s−115\text{ m s}^{-1}, in any direction. Air resistance is negligible; take g=10 m s−2g = 10\text{ m s}^{-2}.

    Use energy conservation to find its speed when it is 10 m10\text{ m} above the ground. (4 marks)
    Level 4 · 4 marksTry it

All 15 kinetic and potential energy questions

Power

22 questions

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  1. 1
    A car of mass 15001500 kg tows a caravan of mass 10001000 kg down a straight road. The road is inclined to the horizontal at an angle α\alpha, where sin⁡α=149\sin\alpha = \frac{1}{49}

    The caravan is attached to the car by a tow bar which is parallel to the road. The tow bar is modelled as a light rod.

    The non-gravitational resistances to the motion are modelled as constant forces, of magnitude 500500 N on the car and 800800 N on the caravan.

    The engine of the car works at a constant rate of 1818 kW.
    (a) Find the acceleration of the car and the caravan when their speed is 10 m s−110\ \text{m s}^{-1}

    (5 marks)

    Later, when the car and the caravan are moving down the road at 12 m s−112\ \text{m s}^{-1}, the tow bar breaks. The caravan continues to move down the road and the resistance to its motion is unchanged.
    (b) Use the work–energy principle to find how far the caravan travels down the road after the tow bar breaks.

    (4 marks)
    Level 4 · 9 marksTry it
  2. 2
    A coach of mass 12 00012\,000 kg is moving up a straight hill which is inclined to the horizontal at an angle α\alpha, where sin⁡α=124\sin\alpha = \frac{1}{24}

    The resistance to the motion of the coach from non-gravitational forces is modelled as a constant force of magnitude RR newtons. The coach is modelled as a particle.

    With its engine working at a constant rate of 7272 kW, the coach moves up the hill at a constant speed of 12 m s−112\ \text{m s}^{-1}
    (a) Find the value of RR.

    (4 marks)

    While the coach is moving up the hill at 12 m s−112\ \text{m s}^{-1}, the rate at which its engine is working is suddenly increased to 9696 kW.
    (b) Find the acceleration of the coach immediately after the rate of working is increased.

    (4 marks)

    Later, the coach is moving up the hill with speed 15 m s−115\ \text{m s}^{-1} when it passes the point AA. At AA the engine is switched off. The coach continues to move up the hill and the resistance to its motion is still RR newtons.
    (c) Use the work–energy principle to find the speed of the coach at the instant when it has travelled 5050 m up the hill from AA.

    (4 marks)
    Level 4 · 12 marksTry it
  3. 3
    A car of mass 1200 kg1200\text{ kg} travels at a constant speed of 20 m s−120\text{ m s}^{-1} up a hill inclined at angle θ\theta to the horizontal, where sin⁡θ=0.05\sin\theta = 0.05. The resistance to motion is constant at 400 N400\text{ N}. Taking g=10 m s−2g = 10\text{ m s}^{-2}, find the power developed by the engine. (5 marks)

    (The diagram is not drawn to scale.)carθF400 Nmg
    Level 4 · 5 marksTry it

All 22 power questions