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Rounding & bounds
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Level 5
Rounding and significant figures
20 questions
Lesson
Not started
Mark as done
k
=
6.0
k = 6.0
k
=
6.0
, correct to
1
1
1
decimal place.
(a)
Write down the error interval for
k
k
k
.
(b)
Maya says, "
k
k
k
could be exactly
6.05
6.05
6.05
." Explain why Maya is wrong.
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Level 5
3 marks
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Estimation
15 questions
Lesson
Not started
Mark as done
A car travels 297 miles and uses 41.3 litres of fuel.
(a)
Work out an estimate for the number of miles the car travels per litre.
(b)
Is your estimate an overestimate or an underestimate? Give a reason.
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Level 5
3 marks
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→
Mark as done
Work out an estimate for the value of
9.12
2
×
2.13
0.485
\dfrac{9.12^2 \times 2.13}{0.485}
0.485
9.1
2
2
×
2.13
You must show your working.
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Level 5
3 marks
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Upper and lower bounds
23 questions
Lesson
Not started
Mark as done
A runner covers a distance of
d
=
84
d = 84
d
=
84
m, correct to the nearest metre, in a time of
t
=
6.2
t = 6.2
t
=
6.2
s, correct to 1 decimal place.
Work out the
upper bound
of the average speed
d
t
\dfrac{d}{t}
t
d
. Give your answer to 2 decimal places.
●●●●●
Level 5
3 marks
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→
Mark as done
k
=
a
b
k = \dfrac{a}{b}
k
=
b
a
, where
a
=
5.4
a = 5.4
a
=
5.4
and
b
=
1.8
b = 1.8
b
=
1.8
, each correct to 1 decimal place.
By considering bounds, work out the value of
k
k
k
to a
suitable degree of accuracy
. You must show all your working and give a reason for your answer.
●●●●●
Level 5
4 marks
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Mark as done
x
=
7.2
x = 7.2
x
=
7.2
and
y
=
4.5
y = 4.5
y
=
4.5
, each correct to 1 decimal place.
Work out the
lower bound
of
x
−
y
x - y
x
−
y
.
●●●●●
Level 5
3 marks
Start
→
Mark as done
A cyclist covers a distance of
d
=
150
d = 150
d
=
150
m, correct to the nearest
10
10
10
m, in a time of
t
=
12.4
t = 12.4
t
=
12.4
s, correct to
1
1
1
decimal place.
Work out the
lower bound
of the cyclist's average speed. Give your answer correct to 3 significant figures.
●●●●●
Level 5
3 marks
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→
Mark as done
v
=
x
y
v = \dfrac{x}{y}
v
=
y
x
, where
x
=
9.6
x = 9.6
x
=
9.6
and
y
=
3.2
y = 3.2
y
=
3.2
, each correct to
1
1
1
decimal place.
By considering bounds, work out the value of
v
v
v
to a suitable degree of accuracy. You must show your working and give a reason for your answer.
●●●●●
Level 5
4 marks
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Mark as done
P
Q
R
PQR
P
QR
is a right-angled triangle.
5.2 cm
7.4 cm
x
P
Q
R
P
Q
=
7.4
PQ = 7.4
P
Q
=
7.4
cm correct to the nearest mm.
Q
R
=
5.2
QR = 5.2
QR
=
5.2
cm correct to the nearest mm.
Calculate the upper bound for the size of the angle marked
x
x
x
.
You must show all your working.
(3 marks)
●●●●●
Level 5
3 marks
Start
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