igureMaths
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Formulae & rearranging
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Browse Formulae & rearranging
40 questions at your level
Difficulty
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Level 1
Level 2
Level 3
Level 4
Level 5
Substituting into formulae
15 questions
Lesson
Not started
Mark as done
y
=
5
t
2
−
3
t
y = 5t^2 - 3t
y
=
5
t
2
−
3
t
Work out the value of
y
y
y
when
t
=
−
2
t = -2
t
=
−
2
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●
Level 4
2 marks
Start
→
Mark as done
v
2
=
u
2
+
2
a
s
v^2 = u^2 + 2as
v
2
=
u
2
+
2
a
s
u
=
3
u = 3
u
=
3
,
a
=
4
a = 4
a
=
4
and
s
=
5
s = 5
s
=
5
.
Given that
v
v
v
is positive, work out the value of
v
v
v
.
●●●●
●
Level 4
3 marks
Start
→
Mark as done
P
=
2
a
−
b
a
+
b
P = \dfrac{2a - b}{a + b}
P
=
a
+
b
2
a
−
b
Work out the value of
P
P
P
when
a
=
4
a = 4
a
=
4
and
b
=
−
2
b = -2
b
=
−
2
●●●●
●
Level 4
3 marks
Start
→
Mark as done
a
=
3
b
2
−
2
c
3
a = 3b^2 - 2c^3
a
=
3
b
2
−
2
c
3
Work out the value of
a
a
a
when
b
=
−
4
b = -4
b
=
−
4
and
c
=
2
c = 2
c
=
2
.
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●
Level 4
3 marks
Start
→
Mark as done
k
=
2
(
l
−
m
)
2
k = 2(l - m)^2
k
=
2
(
l
−
m
)
2
Work out the value of
k
k
k
when
l
=
3
l = 3
l
=
3
and
m
=
7
m = 7
m
=
7
.
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●
Level 4
3 marks
Start
→
Rearranging formulae
16 questions
Lesson
Not started
Mark as done
Make
r
r
r
the subject of
A
=
π
r
2
\;A = \pi r^2
A
=
π
r
2
, where
r
r
r
is positive.
●●●●
●
Level 4
2 marks
Start
→
Mark as done
Make
x
x
x
the subject of
y
=
3
x
+
2
5
\;y = \dfrac{3x + 2}{5}
y
=
5
3
x
+
2
●●●●
●
Level 4
3 marks
Start
→
Mark as done
Make
x
x
x
the subject of
y
=
5
−
2
x
3
\;y = 5 - \dfrac{2x}{3}
y
=
5
−
3
2
x
●●●●
●
Level 4
3 marks
Start
→
Mark as done
Make
r
r
r
the subject of
V
=
4
3
π
r
3
\;V = \dfrac{4}{3}\pi r^3
V
=
3
4
π
r
3
●●●●
●
Level 4
3 marks
Start
→
Changing the subject when it appears twice
11 questions
Lesson
Not started
Mark as done
Make
x
x
x
the subject of
a
x
+
7
=
b
x
+
c
\;ax + 7 = bx + c
a
x
+
7
=
b
x
+
c
●●●●
●
Level 4
3 marks
Start
→
Mark as done
Make
n
n
n
the subject of
m
=
3
(
n
−
5
)
n
\;m = \dfrac{3(n - 5)}{n}
m
=
n
3
(
n
−
5
)
●●●●
●
Level 4
3 marks
Start
→
Mark as done
Make
x
x
x
the subject of
a
(
x
+
2
)
=
b
(
x
−
5
)
\;a(x + 2) = b(x - 5)
a
(
x
+
2
)
=
b
(
x
−
5
)
●●●●
●
Level 4
4 marks
Start
→
Mark as done
Make
t
t
t
the subject of
s
=
2
t
+
3
t
\;s = \dfrac{2t + 3}{t}
s
=
t
2
t
+
3
●●●●
●
Level 4
3 marks
Start
→