A-level · Projectiles

Projectile motion formulaeExam-style questions

The standard results for a projectile launched at speed u and angle θ over level ground — time of flight 2u sinθ/g, greatest height u²sin²θ/(2g), range u²sin2θ/g — and using them in reverse to find u or θ.

17 questions · A-level level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 2Level 3Level 4Level 5
  1. 1
    At time t=0t = 0, a particle leaves the point OO and then moves freely under gravity. Its initial velocity has magnitude uu m s−1^{-1} and is directed upwards at an angle α\alpha to the horizontal. At time tt seconds the particle is at the point (x,y)(x, y) relative to OO, where xx metres is measured horizontally and yy metres is measured vertically upwards.
    (a) Show that the equation of the path of the particle is

    y=xtan⁡α−gx22u2(1+tan⁡2α)y = x\tan\alpha - \frac{gx^2}{2u^2}\left(1 + \tan^2\alpha\right)

    (6 marks)12.5 m20 mθ°U m s⁻¹21 m s⁻¹ABFigure 3 (not accurately drawn)

    A ball is thrown from the point AA, which is 12.512.5 m vertically above horizontal ground. The ball is thrown upwards at an angle of θ°\theta° to the horizontal, with speed UU m s−1^{-1}, and lands on the ground at the point BB. The horizontal distance from AA to BB is 2020 m, as shown in Figure 3.

    The ball is modelled as a particle moving freely under gravity. It is moving with speed 2121 m s−1^{-1} at the instant it reaches BB.
    (b) Use the principle of conservation of mechanical energy to find the value of UU.

    (3 marks)
    (c) Find the value of θ\theta.

    (3 marks)
    Level 5 · 12 marksTry it
  2. 2
    A projectile is launched at speed uu at angle α\alpha above the horizontal over level ground, reaching greatest height HH and range RR.

    Show that HR=tan⁡α4\dfrac{H}{R} = \dfrac{\tan\alpha}{4}. (4 marks)
    Level 5 · 4 marksTry it
  3. 3
    A particle is projected from a point on horizontal ground with speed uu at an angle θ\theta above the horizontal, and moves freely under gravity until it returns to the ground.
    (a) Show that the horizontal range is R=u2sin⁡2θgR = \dfrac{u^2\sin 2\theta}{g}. (5 marks)
    (b) Given that u=28u = 28 m s⁻¹ and R=60R = 60 m, find the two possible values of θ\theta, to 1 decimal place. Take g=9.8g = 9.8 m s⁻². (4 marks)
    (c) State which of your two angles gives the longer time of flight, justifying your answer. (2 marks)
    (d) State one assumption of the model. (1 mark)
    Level 5 · 12 marksTry it