A-level · Projectiles

Projectile motion formulaeExam-style questions

The standard results for a projectile launched at speed u and angle θ over level ground — time of flight 2u sinθ/g, greatest height u²sin²θ/(2g), range u²sin2θ/g — and using them in reverse to find u or θ.

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17 questions · A-level level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 2Level 3Level 4Level 5
  1. 1
    A ball is projected at 1414 m s−1^{-1} at 30∘30^{\circ} above the horizontal over level ground.

    Use T=2usin⁡αgT = \dfrac{2u\sin\alpha}{g} to find the time of flight. (3 marks)
    Level 2 · 3 marksTry it
  2. 2
    A ball is projected at 2828 m s−1^{-1} at 45∘45^{\circ} over level ground.

    Use R=u2sin⁡2αgR = \dfrac{u^{2}\sin 2\alpha}{g} to find the range. (3 marks)
    Level 2 · 3 marksTry it
  3. 3
    A stone is thrown at 21 m s−121\ \text{m s}^{-1} at 45∘45^\circ over level ground. Use R=u2sin⁡2θgR = \dfrac{u^2\sin 2\theta}{g} to find the range. (g=9.8g = 9.8.)
    Level 3 · 2 marksTry it
  4. 4
    A ball is projected at 30 m s−130\ \text{m s}^{-1} at 30∘30^\circ over level ground. Find the time of flight, to 3 s.f. (g=9.8g = 9.8.)
    Level 3 · 2 marksTry it
  5. 5
    A particle is projected at 24 m s−124\ \text{m s}^{-1} at 60∘60^\circ. Use H=u2sin⁡2θ2gH = \dfrac{u^2\sin^2\theta}{2g} to find the greatest height, to 3 s.f. (g=9.8g = 9.8.)
    Level 3 · 2 marksTry it

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