(a) Using ruler and compasses, construct triangle ABC with AB=7 cm, BC=6 cm and AC=5 cm.
(b) Construct the perpendicular bisector of BC and the bisector of angle BAC. Extend both constructed lines far enough for them to cross, and mark the crossing point X. (You may find that X lies outside the triangle.)
(c) Ravi says "X is the same distance from B as from C, and it is also the same distance from AB as from AC." Explain why Ravi is right. ●●●●●Level 56 marksStart→