A-level · Vectors

Position vectorsExam-style questions

Pinning points to the origin with position vectors, the "destination minus start" rule AB = b − a, the distance between two points as |b − a|, the midpoint as ½(a + b), and finding a point that divides a segment in a ratio.

15 questions · A-level level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 2Level 3Level 4Level 5
  1. 1
    ABCDABCD is a quadrilateral. The points AA and BB have position vectors i−3j\mathbf{i} - 3\mathbf{j} and 4i+j4\mathbf{i} + \mathbf{j} respectively.
    (a) Find the length ABAB.

    (1 mark)

    The vertex CC lies on the positive yy-axis, and BC=ABBC = AB.
    (b) Determine the position vector of CC.

    (3 marks)

    The vertex DD is such that AD→=2BC→\overrightarrow{AD} = 2\overrightarrow{BC}.
    (c) Determine the position vector of DD.

    (2 marks)
    (d) State, with a reason, the type of quadrilateral that ABCDABCD is.

    (2 marks)
    Level 4 · 8 marksTry it
  2. 2
    The points AA and BB have position vectors (4−18)\begin{pmatrix} 4 \\ -1 \\ 8 \end{pmatrix} and (6−17)\begin{pmatrix} 6 \\ -1 \\ 7 \end{pmatrix} respectively. The point PP lies on the line through the origin OO and AA, with OP→=tOA→\overrightarrow{OP} = t\overrightarrow{OA}, where tt is a positive constant.
    (a) Write down an expression, in terms of tt, for the distance OPOP.

    (1 mark)

    It is given that BB is equidistant from OO and PP.
    (b) Determine the value of tt.

    (4 marks)
    Level 4 · 5 marksTry it
  3. 3
    The points AA and BB in the xx-yy plane have position vectors a\mathbf{a} and b\mathbf{b} respectively, where a≠b\mathbf{a} \ne \mathbf{b}.
    (a) (i) Write down, in terms of a\mathbf{a} and b\mathbf{b}, the position vector of the point CC for which AA is the midpoint of BCBC.

    (ii) Write down an expression, in terms of a\mathbf{a} and b\mathbf{b}, for the length BCBC.

    (2 marks)

    The point PP has position vector p\mathbf{p}, where ∣p−(2a−b)∣=∣a−b∣\left|\mathbf{p} - (2\mathbf{a} - \mathbf{b})\right| = |\mathbf{a} - \mathbf{b}|.
    (b) (i) Describe the locus of PP.

    (ii) Explain why AA lies on this locus.

    (2 marks)
    (c) In the case where a=(21)\mathbf{a} = \begin{pmatrix} 2 \\ 1 \end{pmatrix} and b=(−24)\mathbf{b} = \begin{pmatrix} -2 \\ 4 \end{pmatrix}, find a cartesian equation of the locus of PP.

    (4 marks)
    Level 4 · 8 marksTry it
  4. 4
    Points AA and BB have position vectors i+2j+2k\mathbf{i} + 2\mathbf{j} + 2\mathbf{k} and 5i+4j+14k5\mathbf{i} + 4\mathbf{j} + 14\mathbf{k}. Find the position vector of the midpoint MM of ABAB, and the distance AMAM.
    Level 4 · 4 marksTry it
  5. 5
    The points AA, BB and CC have position vectors, relative to the origin OO,

    OA→=i+2j+3k,OB→=4i+6j+3k,OC→=i+5j+7k\overrightarrow{OA} = \mathbf{i} + 2\mathbf{j} + 3\mathbf{k}, \qquad \overrightarrow{OB} = 4\mathbf{i} + 6\mathbf{j} + 3\mathbf{k}, \qquad \overrightarrow{OC} = \mathbf{i} + 5\mathbf{j} + 7\mathbf{k}
    (a) Find AB→\overrightarrow{AB} and AC→\overrightarrow{AC}, and show that the triangle ABCABC is isosceles. (4 marks)
    (b) Find the exact length of BCBC. (2 marks)
    (c) Use the cosine rule to find angle BACBAC, correct to 11 decimal place. (3 marks)
    Level 4 · 9 marksTry it

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