A-level · Vectors

Solving geometric problems with vectorsExam-style questions

Using vectors to prove geometry: parallel vectors as scalar multiples, collinear points as parallel vectors through a shared point, dividing a line in a ratio, expressing figures in terms of base vectors, and comparing areas.

20 questions · A-level level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 3Level 4Level 5
  1. 1
    The points AA, BB and CC have coordinates (1,2)(1, 2), (4,8)(4, 8) and (6,12)(6, 12).
    (a) Find AB→\overrightarrow{AB} and BC→\overrightarrow{BC}. (2 marks)
    (b) Show that AA, BB and CC are collinear. (3 marks)
    (c) Find the ratio AB:BCAB : BC. (2 marks)
    Level 3 · 7 marksTry it
  2. 2
    In triangle OABOAB, OA→=a\overrightarrow{OA} = \mathbf{a} and OB→=b\overrightarrow{OB} = \mathbf{b}. The point MM is the midpoint of ABAB, and GG lies on OMOM with OG:GM=2:1OG : GM = 2 : 1.
    (a) Find OM→\overrightarrow{OM} in terms of a\mathbf{a} and b\mathbf{b}. (3 marks)
    (b) Show that OG→=13(a+b)\overrightarrow{OG} = \tfrac13(\mathbf{a} + \mathbf{b}). (3 marks)
    Level 3 · 6 marksTry it
  3. 3
    The vectors a=3i+2j\mathbf{a} = 3\mathbf{i} + 2\mathbf{j} and b=6i+λj\mathbf{b} = 6\mathbf{i} + \lambda\mathbf{j} are parallel. Find the value of λ\lambda. (3 marks)
    Level 3 · 3 marksTry it
  4. 4
    The diagram shows triangle OABOAB, where OA→=a\overrightarrow{OA} = \mathbf{a} and OB→=b\overrightarrow{OB} = \mathbf{b}. The point CC lies on ABAB with AC:CB=2:1AC : CB = 2 : 1, and DD is the midpoint of OCOC. The line through AA and DD meets OBOB at the point EE.aObABCDE(a) Find AD→\overrightarrow{AD} in terms of a\mathbf{a} and b\mathbf{b}.

    (2 marks)
    (b) Explain why AE→=k(2b−5a)\overrightarrow{AE} = k(2\mathbf{b} - 5\mathbf{a}) for some constant kk.

    (2 marks)
    (c) Hence determine the ratio OE:EBOE : EB.

    (4 marks)
    Level 4 · 8 marksTry it
  5. 5
    The diagram shows a cuboid OABCDEFGOABCDEFG. The vertices DD, EE, FF and GG lie vertically above OO, AA, BB and CC respectively. OA→=a\overrightarrow{OA} = \mathbf{a}, OC→=c\overrightarrow{OC} = \mathbf{c} and OD→=d\overrightarrow{OD} = \mathbf{d}.acdOABCDEFGPQThe point PP lies on the edge DGDG with DP:PG=1:3DP : PG = 1 : 3, and the point QQ lies on the edge ABAB with AQ:QB=3:1AQ : QB = 3 : 1.
    (a) Find, in terms of a\mathbf{a}, c\mathbf{c} and d\mathbf{d}, the position vector of the midpoint of PQPQ.

    (4 marks)
    (b) Hence show that the line segments PQPQ and OFOF bisect each other.

    (2 marks)
    Level 4 · 6 marksTry it

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