A-level · Kinematics

Motion in two dimensions with vectorsExam-style questions

Why the a → v → r calculus chain works component-by-component in 2D, that speed is the magnitude of the velocity vector, and how "parallel to" and "perpendicular to" a direction become simple component conditions.

33 questions · A-level level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 2Level 3Level 4Level 5
  1. 1
    [In this question i\mathbf{i} and j\mathbf{j} are horizontal unit vectors directed due east and due north respectively and position vectors are given relative to a fixed origin OO.]

    Two canoes, AA and BB, are moving across a lake. Each canoe moves in a straight line at a constant velocity, and the canoes are modelled as particles.

    Canoe AA passes the point with position vector (−4i+21j)(-4\mathbf{i} + 21\mathbf{j}) m at time t=5t = 5 seconds, and it passes the point with position vector (26i+6j)(26\mathbf{i} + 6\mathbf{j}) m at time t=20t = 20 seconds.
    (a) Find the velocity of AA, giving your answer in terms of i\mathbf{i} and j\mathbf{j}.

    (2 marks)
    (b) Find, in terms of tt, i\mathbf{i} and j\mathbf{j}, the position vector of AA at time tt seconds.

    (2 marks)

    Canoe BB moves with constant velocity (−2i+j) m s−1(-2\mathbf{i} + \mathbf{j})\ \text{m s}^{-1}. When t=0t = 0, BB is at the point with position vector (40i−10j)(40\mathbf{i} - 10\mathbf{j}) m.
    (c) Find the bearing of AA from BB when t=25t = 25, giving your answer to the nearest degree.

    (3 marks)
    Level 3 · 7 marksTry it
  2. 2
    A particle moves in a plane so that at time tt seconds its position vector is r=(t3−2t) i+(3t2−t) j\mathbf{r} = (t^3 - 2t)\,\mathbf{i} + (3t^2 - t)\,\mathbf{j} metres. Find
    (a) its velocity at time tt,
    (b) its acceleration at time tt, and (c) its speed when t=1t = 1.
    Level 3 · 5 marksTry it
  3. 3
    A particle moves with constant acceleration a=(−i+2j) m s−2\mathbf{a} = (-\mathbf{i} + 2\mathbf{j})\ \text{m s}^{-2}. At t=0t = 0 its velocity is u=(4i−3j) m s−1\mathbf{u} = (4\mathbf{i} - 3\mathbf{j})\ \text{m s}^{-1}. Find
    (a) its velocity when t=3t = 3,
    (b) its speed when t=3t = 3, and (c) the value of tt at which it is moving parallel to j\mathbf{j}.
    Level 3 · 4 marksTry it
  4. 4
    A particle moves in a plane so that at time tt seconds its position vector is

    r=(3t2−1) i+(2t+4) j metres\mathbf{r} = (3t^{2} - 1)\,\mathbf{i} + (2t + 4)\,\mathbf{j} \text{ metres}

    Find the speed of the particle when t=2t = 2, giving your answer in the form k37k\sqrt{37} m s−1^{-1}. (4 marks)
    Level 3 · 4 marksTry it
  5. 5
    A particle has initial velocity (2i−3j)(2\mathbf{i} - 3\mathbf{j}) m s−1^{-1} and moves with constant acceleration (4i+j)(4\mathbf{i} + \mathbf{j}) m s−2^{-2}.

    Find its velocity after 33 seconds, and describe the direction of motion at that instant. (3 marks)
    Level 3 · 3 marksTry it

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