GCSE · Vectors

Vector proofsExam-style questions

What a vector equation actually proves — a scalar multiple gives parallel and nothing more, a multiple plus a shared point gives collinear — and how to write the conclusion in the form a mark scheme rewards.

11 questions · GCSE (Higher) level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 3Level 4Level 5
  1. 1
    OABCOABC is a parallelogram, with OA→=a\overrightarrow{OA} = \mathbf{a} and OC→=b\overrightarrow{OC} = \mathbf{b}.

    MM is the midpoint of ABAB.

    NN is the point on the diagonal OBOB such that ON→=23OB→\overrightarrow{ON} = \tfrac{2}{3}\overrightarrow{OB}.abOABCMNDiagram not accurately drawn.

    (a) Find CN→\overrightarrow{CN} in terms of a\mathbf{a} and b\mathbf{b}. Give your answer in its simplest form.

    (b) Prove that CC, NN and MM lie on the same straight line.
    Level 5 · 7 marksTry it
  2. 2
    OABOAB is a triangle, with OA→=6a\overrightarrow{OA} = 6\mathbf{a} and OB→=6b\overrightarrow{OB} = 6\mathbf{b}.

    MM is the midpoint of OAOA.

    NN is the point on ABAB such that AN:NB=2:1AN : NB = 2 : 1.

    PP is the point on OBOB extended such that OP→=p b\overrightarrow{OP} = p\,\mathbf{b}, where pp is a number.

    (a) Find MN→\overrightarrow{MN} in terms of a\mathbf{a} and b\mathbf{b}. Give your answer in its simplest form.

    (b) MM, NN and PP lie on the same straight line.

    Work out the value of pp.
    Level 5 · 6 marksTry it
  3. 3
    OACBOACB is a parallelogram.

    OA→=a\overrightarrow{OA} = \mathbf{a} and OB→=b\overrightarrow{OB} = \mathbf{b}

    MM is the midpoint of ACAC and NN is the midpoint of BCBC.abOACBMNDiagram NOT accurately drawn

    Prove that MNMN is parallel to ABAB. (4 marks)
    Level 5 · 4 marksTry it
  4. 4
    OABOAB is a triangle. OA→=2a\overrightarrow{OA} = 2\mathbf{a} and OB→=2b\overrightarrow{OB} = 2\mathbf{b}.

    PP is the point on ABAB such that AP:PB=1:3AP : PB = 1 : 3. QQ is the point on OBOB such that OQ:QB=1:3OQ : QB = 1 : 3.

    Prove that PQPQ is parallel to OAOA. [5]
    Level 5 · 5 marksTry it
  5. 5
    ABCDABCD is a parallelogram.4a6bABCDEFGAB→=4a\overrightarrow{AB} = 4\mathbf{a} \qquad AD→=6b\overrightarrow{AD} = 6\mathbf{b}

    EE is the point on ABAB such that AE:EB=1:3AE : EB = 1 : 3

    FF is the midpoint of the diagonal ACAC.

    The side BCBC is extended to the point GG, where BG→=kBC→\overrightarrow{BG} = k\overrightarrow{BC}

    EE, FF and GG lie on a straight line.

    Find the value of kk.

    You must show all your working.

    (5 marks)
    Level 5 · 5 marksTry it