GCSE · Vectors

Vector proofsExam-style questions

What a vector equation actually proves — a scalar multiple gives parallel and nothing more, a multiple plus a shared point gives collinear — and how to write the conclusion in the form a mark scheme rewards.

11 questions · GCSE (Higher) level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 3Level 4Level 5
  1. 1
    PP, QQ, RR and SS are four points. PQ→=2a+6b\overrightarrow{PQ} = 2\mathbf{a} + 6\mathbf{b} and RS→=3a+9b\overrightarrow{RS} = 3\mathbf{a} + 9\mathbf{b}.

    (a) Show that PQPQ is parallel to RSRS.

    (b) Freya says: "This working also proves that PP, QQ, RR and SS all lie on the same straight line."

    Freya is wrong. Explain why.
    Level 3 · 3 marksTry it
  2. 2
    AA, BB and CC are three points.

    AB→=4a−2b\overrightarrow{AB} = 4\mathbf{a} - 2\mathbf{b} and BC→=10a−5b\overrightarrow{BC} = 10\mathbf{a} - 5\mathbf{b}.

    Prove that AA, BB and CC are collinear.
    Level 3 · 3 marksTry it
  3. 3
    OABOAB is a triangle. OA→=2a\overrightarrow{OA} = 2\mathbf{a} and OB→=2b\overrightarrow{OB} = 2\mathbf{b}.

    MM is the midpoint of OAOA and NN is the midpoint of OBOB.OABMN2a2bDiagram not accurately drawn.

    (a) Find MN→\overrightarrow{MN} in terms of a\mathbf{a} and b\mathbf{b}. Give your answer in its simplest form.

    (b) Prove that MNMN is parallel to ABAB.

    (c) Hence write down the ratio MN:ABMN : AB.
    Level 4 · 6 marksTry it
  4. 4
    PQRSPQRS is a quadrilateral.

    PQ→=5a+2b\overrightarrow{PQ} = 5\mathbf{a} + 2\mathbf{b}, QR→=3a−4b\quad\overrightarrow{QR} = 3\mathbf{a} - 4\mathbf{b}, RS→=−5a−2b\quad\overrightarrow{RS} = -5\mathbf{a} - 2\mathbf{b}.

    (a) Find PR→\overrightarrow{PR} in terms of a\mathbf{a} and b\mathbf{b}. Give your answer in its simplest form.

    (b) Prove that PQRSPQRS is a parallelogram.
    Level 4 · 5 marksTry it
  5. 5
    OO, AA and BB are three points, with OA→=a\overrightarrow{OA} = \mathbf{a} and OB→=b\overrightarrow{OB} = \mathbf{b}.

    The point CC is such that OC→=15a+45b\overrightarrow{OC} = \tfrac{1}{5}\mathbf{a} + \tfrac{4}{5}\mathbf{b}.

    (a) Show that CC lies on the line ABAB.

    (b) Write down the ratio AC:CBAC : CB.
    Level 4 · 4 marksTry it

6 more questions on vector proofs

Free with an account — just an email, no card. The whole bank, every mark scheme and worked solution.

Start free