GCSE · Vectors

Column vectorsExam-style questions

A vector is a translation — so far across, so far up — not a place. How to add, subtract and scale columns, why a scalar multiple is parallel, how Pythagoras gives the magnitude, and why the journey from A to B is destination minus start.

16 questions · GCSE (Higher) level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 1Level 2Level 3Level 4Level 5
  1. 1
    a=(31)\mathbf{a} = \begin{pmatrix} 3 \\ 1 \end{pmatrix} and b=(25)\mathbf{b} = \begin{pmatrix} 2 \\ 5 \end{pmatrix}. Work out a+b\mathbf{a} + \mathbf{b}.
    Level 1 · 1 markTry it
  2. 2
    a=(4−2)\mathbf{a} = \begin{pmatrix} 4 \\ -2 \end{pmatrix}. Work out 3a3\mathbf{a}.
    Level 1 · 1 markTry it
  3. 3
    p=(62)\mathbf{p} = \begin{pmatrix} 6 \\ 2 \end{pmatrix} and q=(14)\mathbf{q} = \begin{pmatrix} 1 \\ 4 \end{pmatrix}. Work out p−q\mathbf{p} - \mathbf{q}.
    Level 1 · 1 markTry it
  4. 4
    a=(5−2)\mathbf{a} = \binom{5}{-2} and b=(−34)\mathbf{b} = \binom{-3}{4}.

    (a) Work out a+b\mathbf{a} + \mathbf{b} as a column vector.

    (b) Work out a−b\mathbf{a} - \mathbf{b} as a column vector.

    (c) Work out 3b3\mathbf{b} as a column vector.
    Level 2 · 3 marksTry it
  5. 5
    a=(23)\mathbf{a} = \begin{pmatrix} 2 \\ 3 \end{pmatrix} and b=(−14)\mathbf{b} = \begin{pmatrix} -1 \\ 4 \end{pmatrix}

    (a) Work out a−b\mathbf{a} - \mathbf{b} (1 mark)

    (b) Work out 3a+2b3\mathbf{a} + 2\mathbf{b} (1 mark)

    (c) PP is the point (1,2)(1, 2) and QQ is the point (4,8)(4, 8). Write PQ→\overrightarrow{PQ} as a column vector. (1 mark)
    Level 2 · 3 marksTry it

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