A-level · Differentiation

Implicit differentiationExam-style questions

Finding the gradient of a curve whose equation cannot be rearranged into y = f(x). Why such curves need a new method; differentiating a y-term with the chain rule; products of x and y; collecting dy/dx and why the answer contains both x and y; gradients, tangents and normals at a point; and finding where the tangent is horizontal or vertical.

40 questions · A-level level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 3Level 4Level 5
  1. 1
    The curve CC has equation

    2x2+xy+y2=162x^2 + xy + y^2 = 16.
    (a) Show that dydx=−4x+yx+2y\dfrac{dy}{dx} = -\dfrac{4x + y}{x + 2y}. (4 marks)
    (b) The point P(2,2)P(2, 2) lies on CC. Find an equation of the tangent to CC at PP, giving your answer in the form ax+by+c=0ax + by + c = 0, where aa, bb and cc are integers. (2 marks)
    (c) Find a relationship between xx and yy that holds at any point of CC where the tangent is parallel to the xx-axis. (1 mark)
    Level 4 · 7 marksTry it
  2. 2
    The curve CC has equation

    x2+xy+y2=12x^2 + xy + y^2 = 12

    Find the coordinates of the two points on CC at which the tangent is parallel to the xx-axis. (7 marks)
    Level 4 · 7 marksTry it
  3. 3
    The curve CC has equation xy=12xy = 12.

    Find an equation of the tangent to CC at the point (3,4)(3, 4), giving your answer in the form ax+by=cax + by = c with integer coefficients. (4 marks)
    Level 4 · 4 marksTry it
  4. 4
    The curve CC has equation

    x2+3xy−y2=3x^2 + 3xy - y^2 = 3

    The point P(1,2)P(1, 2) lies on CC.

    Find an equation of the tangent to CC at PP. (7 marks)
    Level 4 · 7 marksTry it
  5. 5
    A curve has equation

    xe2y+y2−3x2=kxe^{2y} + y^2 - 3x^2 = k

    where kk is a constant.

    A stationary point of the curve has yy-coordinate ln⁡3\ln 3

    Determine the exact value of kk

    (7 marks)
    Level 4 · 7 marksTry it

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