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Pure · Differentiation

Chapter 1 · 4

The idea

Implicit differentiation

Differentiating a relation that mixes x and y — like x² + y² = 25 — without solving for y, by differentiating both sides with respect to x and treating y as a function of x (so d/dx of y² is 2y dy/dx).

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Pure · Differentiation

Implicit differentiation

Differentiating a relation that mixes x and y — like x² + y² = 25 — without solving for y, by differentiating both sides with respect to x and treating y as a function of x (so d/dx of y² is 2y dy/dx).

Why it works

When y won't isolate

Not every curve can be tidied into y=f(x)y = f(x). The circle x2+y2=25x^2 + y^2 = 25 would split into two half-curves y=±25−x2y = \pm\sqrt{25 - x^2}; relations like x3+y3=6xyx^3 + y^3 = 6xy resist rearranging at all. Implicit differentiation finds the gradient without ever isolating yy.

The chain-rule tax

The one idea you need: yy is still a function of xx, even if you can't see the formula. So whenever you differentiate a term containing yy, the chain rule fires and a dydx\frac{dy}{dx} drops out. Differentiating y2y^2 with respect to xx:

ddx(y2)=2y dydx\frac{d}{dx}\big(y^2\big) = 2y\,\frac{dy}{dx}

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