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Pure · Algebra & functions

Chapter 1 · 4

The idea

Polynomials and the factor theorem

The factor theorem — why f(a) = 0 means (x − a) is a factor — and how to use it with algebraic division to factorise and solve cubics.

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Pure · Algebra & functions

Polynomials and the factor theorem

The factor theorem — why f(a) = 0 means (x − a) is a factor — and how to use it with algebraic division to factorise and solve cubics.

Why it works

Finding the first factor

A quadratic you can usually factorise by inspection. A cubic like x3−3x2+4x^3 - 3x^2 + 4 is harder — you need a way to find a first factor before the rest falls out. That's what the factor theorem gives you.

The factor theorem

Divide a polynomial f(x)f(x) by (x−a)(x - a). Whatever happens, you can write f(x)=(x−a) q(x)+r,f(x) = (x - a)\,q(x) + r, where q(x)q(x) is the quotient and rr is a constant remainder. Now substitute x=ax = a: the (x−a)(x-a) term becomes zero and takes q(x)q(x) with it, leaving f(a)=r.f(a) = r. So the value f(a)f(a) is the remainder. And (x−a)(x - a) divides exactly — i.e. is a factor — precisely when that remainder is zero:

(x−a) is a factor of f(x)  ⟺  f(a)=0(x - a) \text{ is a factor of } f(x) \iff f(a) = 0

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