A-level · Trigonometry

Addition formulaeExam-style questions

The compound-angle formulae for sin(A±B), cos(A±B) and tan(A±B) — the sign patterns to get right, and using them for exact values of non-standard angles, expanding, proving identities and solving equations.

24 questions · A-level level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 3Level 4Level 5
  1. 1
    In this question you must show detailed reasoning.
    (a) (i) Starting from the identity for tan⁡(A+B)\tan(A + B), show that tan⁡3θ≡3tan⁡θ−tan⁡3θ1−3tan⁡2θ.\tan 3\theta \equiv \frac{3\tan\theta - \tan^3\theta}{1 - 3\tan^2\theta}.

    (ii) Solve the equation tan⁡3θ=1\tan 3\theta = 1 for 0∘≤θ≤180∘0^\circ \le \theta \le 180^\circ.

    (5 marks)
    (b) (i) Expand (x+1)(x2−4x+1)(x + 1)(x^2 - 4x + 1).

    (ii) Hence solve the equation x3−3x2−3x+1=0x^3 - 3x^2 - 3x + 1 = 0, giving each root in exact form.

    (3 marks)
    (c) By considering the values of tan⁡θ\tan\theta at the solutions found in part (a)(ii), and using part (b)(ii), show that tan⁡15∘=2−3\tan 15^\circ = 2 - \sqrt3.

    (2 marks)
    Level 5 · 10 marksTry it
  2. 2
    (a) Show that sin⁡(A+B)−sin⁡(A−B)≡2cos⁡Asin⁡B\sin(A+B) - \sin(A-B) \equiv 2\cos A\sin B.
    (b) By writing 3x=2x+x3x = 2x + x and x=2x−xx = 2x - x, solve sin⁡3x=sin⁡x\sin 3x = \sin x for 0≤x≤π0 \le x \le \pi, giving your answers as exact multiples of π\pi.
    Level 5 · 6 marksTry it
  3. 3
    hxyPQRNThe diagram shows triangle PQRPQR. The perpendicular from RR to PQPQ meets PQPQ at NN. Angle PRN=xPRN = x, angle NRQ=yNRQ = y and the length RN=hRN = h.
    (a) (i) Find the length PRPR in terms of hh and xx.

    (ii) Write down the length QRQR in terms of hh and yy.

    (iii) By finding the area of triangle PQRPQR in two different ways, show that sin⁡(x+y)≡sin⁡xcos⁡y+cos⁡xsin⁡y\sin(x + y) \equiv \sin x\cos y + \cos x\sin y.

    (6 marks)
    (b) Given that sin⁡(α+60∘)=cos⁡(α−45∘)\sin(\alpha + 60^\circ) = \cos(\alpha - 45^\circ), show that tan⁡α=6+3−2−2\tan\alpha = \sqrt6 + \sqrt3 - \sqrt2 - 2.

    (5 marks)
    Level 5 · 11 marksTry it