A-level · Numerical methods

The trapezium ruleExam-style questions

Estimating a definite integral by slicing the area into trapezium-topped strips: the formula (h/2)[y₀ + yₙ + 2(y₁ + … + y_(n−1))], choosing h, and deciding whether the estimate is an over- or under-estimate from the curve's shape.

28 questions · A-level level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 2Level 3Level 4Level 5
  1. 1
    A curve has equation y=x2+53y = \sqrt[3]{x^2 + 5}

    The table below gives the value of yy, to 3 decimal places, at six equally spaced values of xx.

    x11.522.533.5y1.8171.9352.0802.2412.4102.584\begin{array}{c|cccccc} x & 1 & 1.5 & 2 & 2.5 & 3 & 3.5 \\ \hline y & 1.817 & 1.935 & 2.080 & 2.241 & 2.410 & 2.584 \end{array}
    (a) Using the trapezium rule with all the values of yy in the given table, obtain an estimate for

    ∫13.5x2+53 dx\int_{1}^{3.5} \sqrt[3]{x^2 + 5}\,\mathrm{d}x

    giving your answer to 3 significant figures.

    (3 marks)

    Using your answer to part (a) and making your method clear, estimate
    (b) (i) ∫13.5(4+x2+53)dx\displaystyle\int_{1}^{3.5} \left(4 + \sqrt[3]{x^2 + 5}\right)\mathrm{d}x

    (ii) ∫13.58x2+403 dx\displaystyle\int_{1}^{3.5} \sqrt[3]{8x^2 + 40}\,\mathrm{d}x

    (3 marks)
    Level 3 · 6 marksTry it
  2. 2
    A continuous curve has equation y=log⁡3(2x+5)y = \log_3(2x + 5)

    The table below gives values of yy for this curve, each to 4 decimal places where appropriate.

    x00.40.81.21.62y1.46501.60011.71771.82181.91532\begin{array}{c|cccccc} x & 0 & 0.4 & 0.8 & 1.2 & 1.6 & 2 \\ \hline y & 1.4650 & 1.6001 & 1.7177 & 1.8218 & 1.9153 & 2 \end{array}

    Using the trapezium rule with all the values of yy in the given table,
    (a) find an estimate for

    ∫02log⁡3(2x+5) dx\int_{0}^{2} \log_3(2x + 5)\,\mathrm{d}x

    giving your answer to 3 decimal places.

    (3 marks)
    (b) Using your answer to part (a) and making your method clear, estimate

    (i) ∫02log⁡32x+5 dx\displaystyle\int_{0}^{2} \log_3\sqrt{2x + 5}\,\mathrm{d}x

    (ii) ∫02log⁡3(18x+45) dx\displaystyle\int_{0}^{2} \log_3(18x + 45)\,\mathrm{d}x

    (2 marks)
    Level 3 · 5 marksTry it
  3. 3
    Use the trapezium rule with 4 strips to estimate ∫021+x3 dx\displaystyle\int_0^2 \sqrt{1 + x^3}\,dx, giving your answer to 3 decimal places.
    Level 3 · 3 marksTry it
  4. 4
    (a) Use the trapezium rule with 4 strips to estimate ∫01ex2 dx\displaystyle\int_0^1 e^{x^2}\,dx to 3 decimal places.
    (b) State, with a reason, whether this is an over- or under-estimate.
    Level 3 · 5 marksTry it
  5. 5
    (a) Use the trapezium rule with 4 strips to estimate ∫151x dx\displaystyle\int_1^5 \dfrac1x\,dx to 4 decimal places.
    (b) The exact value is ln⁡5=1.6094\ln 5 = 1.6094. Explain why the estimate is larger.
    Level 3 · 5 marksTry it

12 more questions on the trapezium rule

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