A-level · Numerical methods

The Newton–Raphson methodExam-style questions

A fast iteration that uses the tangent — x_(n+1) = x_n − f(x_n)/f'(x_n) — its geometric meaning, why it converges so quickly, and the cases where it fails (a horizontal tangent or a poor starting value).

23 questions · A-level level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 2Level 3Level 4Level 5
  1. 1
    Using the Newton–Raphson method on f(x)=x3−5f(x) = x^3 - 5 with x0=2x_0 = 2, find x1x_1 and x2x_2 to 4 decimal places. (This estimates 53\sqrt[3]{5}.)
    Level 3 · 3 marksTry it
  2. 2
    The equation ex+x=4e^x + x = 4 has a root near x=1x = 1. Use the Newton–Raphson method with x0=1x_0 = 1 to find x1x_1 and x2x_2 to 4 decimal places.
    Level 3 · 3 marksTry it
  3. 3
    f(x)=x3+x−1f(x) = x^3 + x - 1. Using Newton–Raphson with x0=1x_0 = 1, find x1x_1 and x2x_2 to 4 decimal places.
    Level 3 · 3 marksTry it
  4. 4
    A student applies the Newton–Raphson method to f(x)=x3−2x−5f(x) = x^3 - 2x - 5, whose only real root is near 2.092.09, but starts at x0=0x_0 = 0. Find x1x_1 and explain why this starting value is a poor choice.
    Level 3 · 3 marksTry it
  5. 5
    (a) Show that applying the Newton–Raphson method to f(x)=x2−Nf(x) = x^2 - N gives the iteration xn+1=12(xn+Nxn)x_{n+1} = \dfrac12\left(x_n + \dfrac{N}{x_n}\right).
    (b) Hence, with N=10N = 10 and x0=3x_0 = 3, estimate 10\sqrt{10} to 4 decimal places.
    Level 3 · 4 marksTry it

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