A-level · Moments

Equilibrium of rigid bodiesExam-style questions

A rigid body in equilibrium needs both zero resultant force and zero resultant moment — using these two conditions to find the reaction forces on a supported beam, and taking moments about a support to eliminate an unknown.

22 questions · A-level level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 2Level 3Level 4Level 5
  1. 1
    A uniform rod ABAB of length 33 m and weight 6060 N is freely hinged at AA and held in equilibrium by a string attached at BB. The string makes an angle of 30∘30^\circ with the rod, which is horizontal. Find the tension in the string.
    Level 5 · 2 marksTry it
  2. 2
    Figure 2 shows a uniform rod ABAB of mass 88 kg and length 33 m, freely hinged to a vertical wall at AA. The rod is held horizontal by a light inextensible string joining BB to a point CC on the wall vertically above AA, where angle ABC=40∘ABC = 40^\circ.3 m40°8g NABCFigure 2 (not accurately drawn)
    (a) Find the tension in the string, giving your answer to 33 significant figures. (5 marks)
    (b) Find the magnitude and direction of the force exerted by the hinge on the rod. (6 marks)
    Level 5 · 11 marksTry it
  3. 3
    A uniform ladder ABAB, of length 88 m and mass 1212 kg, rests with AA on rough horizontal ground and BB against a smooth vertical wall. The ladder makes an angle of 60∘60^\circ with the ground. A decorator of mass 6060 kg stands at the point CC on the ladder, where AC=6AC = 6 m. The ladder is on the point of slipping. Take g=9.8g = 9.8 m s⁻².60°CAB(a) Explain what the modelling assumptions "smooth wall" and "uniform ladder" allow you to say about the forces acting. (2 marks)
    (b) Find the magnitude of the normal reaction of the ground at AA. (2 marks)
    (c) By taking moments about AA, find the magnitude of the normal reaction of the wall at BB, giving your answer to 3 significant figures. (6 marks)
    (d) Find the coefficient of friction between the ladder and the ground, giving your answer in exact form and to 3 significant figures. (4 marks)
    (e) The decorator claims he could safely stand at the very top of the ladder. Comment on this claim, using your model. (1 mark)
    Level 5 · 15 marksTry it
  4. 4
    A uniform ladder ABAB, of length 55 m and mass 1212 kg, rests in equilibrium with the end AA on rough horizontal ground and the end BB against a smooth vertical wall. The ladder lies in a vertical plane perpendicular to the wall, and AA is 33 m from the foot of the wall. The coefficient of friction between the ladder and the ground is 0.450.45.

    A decorator of mass 6060 kg stands on the ladder at the point CC, where AC=xAC = x metres. The ladder is modelled as a uniform rod and the decorator as a particle. Take g=9.8g = 9.8 m s⁻².
    (a) Show that the magnitude of the force exerted by the wall on the ladder is (44.1+88.2x)(44.1 + 88.2x) N. (4 marks)
    (b) Find the greatest value of xx for which the ladder does not slip. (4 marks)
    (c) The decorator needs to stand at BB. To make this possible, a second person stands on the ladder at AA. Find the least mass of the second person for which the ladder remains in equilibrium with the decorator at BB. (5 marks)
    (d) In reality the wall is not perfectly smooth. State, with a reason, how this would affect your answer to part (b). (2 marks)
    Level 5 · 15 marksTry it
  5. 5
    A builder uses a uniform plank ABAB, of length 2a2a and mass mm, as a ramp up to a skip. The end AA of the plank is on horizontal ground, and the plank rests on the top edge of one side of the skip at the point CC. This edge is horizontal, at a height hh above the ground, and is perpendicular to the vertical plane containing the plank. The plank is inclined at an angle α\alpha to the horizontal, where sin⁡α=0.6\sin\alpha = 0.6. A man of mass 6m6m stands on the plank at the point DD, where AD=dAD = d (see diagram).hdαABCDskipIn the model used, the man is treated as a particle, the ground as rough and the edge of the skip as smooth.
    (a) Show that the normal contact force between the plank and the skip is 12mg(a+6d)25h\dfrac{12mg(a + 6d)}{25h}.

    (4 marks)

    The plank is on the point of slipping, and the coefficient of friction between the plank and the ground is 0.30.3.
    (b) Show that h=k(a+6d)h = k(a + 6d), where kk is a constant to be determined.

    (7 marks)
    (c) Hence find, in terms of aa, the greatest possible value of dd.

    (2 marks)
    (d) State one improvement that could be made to the model.

    (1 mark)
    Level 5 · 14 marksTry it

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