A-level · Kinematics

Kinematics with calculus (a → v → s)Exam-style questions

Why integrating acceleration gives velocity and integrating velocity gives displacement, where the suvat formulas actually come from, and why they silently break the moment acceleration varies.

22 questions · A-level level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 2Level 3Level 4Level 5
  1. 1
    In this question you must show all stages of your working.

    Solutions relying on calculator technology are not acceptable.

    A particle PP travels along a straight line. Its speed at time tt seconds is vv m s−1^{-1}, where

    v={2t+30⩽t⩽k3t+12k<t⩽30v = \begin{cases} 2t + 3 & 0 \leqslant t \leqslant k \\ 3\sqrt{t} + 12 & k < t \leqslant 30 \end{cases}

    and kk is a constant.

    Given that vv is continuous for 0⩽t⩽300 \leqslant t \leqslant 30,
    (a) show that k=9k = 9. You must make your reasoning clear.

    (3 marks)
    (b) Find the acceleration of PP when t=16t = 16

    (3 marks)

    When t=0t = 0, PP is at the fixed point OO on the line.
    (c) Find the distance OPOP when t=25t = 25

    (7 marks)
    Level 5 · 13 marksTry it
  2. 2
    In this question, i\mathbf{i} and j\mathbf{j} denote unit vectors due east and due north respectively.

    A jet ski JJ moves on the surface of a calm sea. JJ, together with its rider, has mass 230230 kg and is modelled as a particle. At time tt seconds, where t≥0t \geq 0, the velocity of JJ is v m s−1\mathbf{v}\ \text{m s}^{-1} and the resultant horizontal force acting on JJ is F\mathbf{F} N, where

    v=(4t−11)i+(t2−5t+9)j.\mathbf{v} = (4t - 11)\mathbf{i} + (t^2 - 5t + 9)\mathbf{j}.
    (a) Show that JJ is never stationary.

    (2 marks)
    (b) Find, in terms of i\mathbf{i} and j\mathbf{j}, the acceleration of JJ at time tt.

    (1 mark)
    (c) Determine the magnitude of F\mathbf{F} at the instant when JJ is moving north-west. Give your answer correct to 3 significant figures.

    (5 marks)

    The position vector of JJ relative to a fixed point OO is r\mathbf{r} m. When t=3t = 3, r=−29i−7.5j\mathbf{r} = -29\mathbf{i} - 7.5\mathbf{j}.
    (d) Determine the bearing of JJ from OO when t=6t = 6.

    (5 marks)
    Level 5 · 13 marksTry it
  3. 3
    In this question, i\mathbf{i} and j\mathbf{j} denote unit vectors due east and due north respectively.

    Two horizontal forces act on a particle PP of mass 55 kg, which moves on a smooth horizontal plane. One force is constant and equal to (−13i+12j)(-13\mathbf{i} + 12\mathbf{j}) N; at time tt seconds, where t≥0t \geq 0, the other force is ((3t2+1)i−6tj)\left((3t^2 + 1)\mathbf{i} - 6t\mathbf{j}\right) N. No other horizontal force acts on PP. When t=0t = 0, PP is at rest at the fixed point OO.
    (a) Determine the value of tt for which the forces acting on PP are in equilibrium.

    (2 marks)
    (b) Determine the speed of PP at the instant when PP is moving due east.

    (6 marks)
    (c) Determine the distance of PP from OO when t=5t = 5.

    (5 marks)
    Level 5 · 13 marksTry it
  4. 4
    A tram starts from rest at a stop and moves along a straight horizontal track towards the next stop. For the first 40 seconds of its journey, its velocity v m s−1v\text{ m s}^{-1} at time tt seconds after it starts is modelled by

    v=kt−0.015t2,v = kt - 0.015t^2,

    where kk is a constant.

    At the instant when t=40t = 40, the tram is decelerating at 0.3 m s−20.3\text{ m s}^{-2}. After this, the tram continues to decelerate at a constant 0.3 m s−20.3\text{ m s}^{-2} until it comes to rest at the next stop.
    (a) Find the value of kk.

    (3 marks)
    (b) Find the distance between the two stops.

    (7 marks)
    Level 5 · 10 marksTry it
  5. 5
    The velocity of a particle PP, moving in a straight line, is v m s−1v\text{ m s}^{-1} at time tt seconds, where

    v=ktfor 0⩽t⩽4,v = kt \quad \text{for } 0 \leqslant t \leqslant 4,

    v=16k(t−8)(t−10)for 4⩽t⩽10,v = \tfrac16 k(t - 8)(t - 10) \quad \text{for } 4 \leqslant t \leqslant 10,

    and kk is a positive constant.
    (a) Describe the graph of vv against tt for 0⩽t⩽100 \leqslant t \leqslant 10. Your description should include the shape of each section of the graph, the value of vv, in terms of kk, when t=4t = 4, and the values of tt at which the graph meets the tt-axis.

    (3 marks)
    (b) State the value of tt for which dvdt=0\dfrac{dv}{dt} = 0.

    (1 mark)
    (c) In this question you must show detailed reasoning.

    It is given that PP travels a total distance of 6565 m in the first 10 seconds of its motion.

    Find the value of kk.

    (6 marks)
    Level 5 · 10 marksTry it