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Algebra · Algebraic manipulation

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Factorising with common factors

Why factorising is expansion run backwards, what "factorise fully" demands, and why a difference of two squares splits instantly — plus what the factorised form is actually FOR.

Algebra · Algebraic manipulation

Factorising with common factors

Why factorising is expansion run backwards, what "factorise fully" demands, and why a difference of two squares splits instantly — plus what the factorised form is actually FOR.

Why it works

Factorising is expanding in reverse — rewriting a sum as a product. 6x+156x + 15: both terms are divisible by 3, so pull the 3 out front and record what's left inside: 3(2x+5)3(2x + 5). Expanding the answer must recreate the original — that check is free and catches nearly every slip.

"Factorise fully" means the HIGHEST common factor comes out — the biggest number that divides every coefficient, and each shared letter at its lowest power. For 12x2y18xy212x^2y - 18xy^2: numbers give 6, the xx's share one xx, the yy's share one yy, so

12x2y18xy2=6xy(2x3y).12x^2y - 18xy^2 = 6xy(2x - 3y).

Taking out less — say 6(2x2y3xy2)6(2x^2y - 3xy^2) — is not wrong, but it isn't full: the inside still has a common factor, and the exam mark says fully.

The factor comes OUT, it doesn't vanish. 12x2+8x12x^2 + 8x is 4x(3x+2)4x(3x + 2), not 3x+23x + 2 — dividing the expression by 4x4x changes its value. Factorised form is the same expression, re-packaged as a product.

A difference of two squares needs no factor hunt. y249=(y+7)(y7)y^2 - 49 = (y + 7)(y - 7): expanding gives cross terms 7y+7y-7y + 7y that cancel, which is exactly why no middle term appears. Anything of the shape (square)(square)\text{(square)} - \text{(square)} splits the same way, letters included: 4a225b2=(2a+5b)(2a5b)4a^2 - 25b^2 = (2a + 5b)(2a - 5b). But x29x^2 - 9 is NOT (x3)2(x - 3)^2 — that expands to x26x+9x^2 - 6x + 9; a square of a bracket always carries its middle term.

Why factorise at all? A product reveals what a sum hides: factors show what an expression is divisible by. That's the engine of solving (zero-product rule), of cancelling in fractions, and of proof — e.g. (2n+1)2(2n1)2(2n+1)^2 - (2n-1)^2 looks opaque, but as a difference of two squares it's (4n)(2)=8n(4n)(2) = 8n: visibly a multiple of 8 for every whole nn.