A-level · Forces & Newton's laws

Statics — equilibrium under several forcesExam-style questions

A particle in equilibrium has zero resultant, so resolving in two perpendicular directions gives two equations — used to find unknown forces or angles, including on rough slopes where friction is at its limit (F = μR) on the point of moving.

17 questions · A-level level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 3Level 4Level 5
  1. 1
    0.7 m2.4 m7 NABCFigure 1 (not accurately drawn)

    The ends of a light inextensible string are fixed to the points AA and BB on a horizontal beam, where AB=0.7AB = 0.7 m. A small smooth ring of mass MM kg is threaded on the string.

    A horizontal force of magnitude 77 N is applied to the ring. The ring hangs in equilibrium at the point CC, 2.42.4 m vertically below BB, with the string taut, as shown in Figure 1. The horizontal force acts in the vertical plane containing the string.

    The tension in the string is TT newtons.
    (a) Find the value of TT

    (3 marks)
    (b) Find the value of MM

    (3 marks)
    Level 3 · 6 marksTry it
  2. 2
    A particle of weight 5050 N rests on a rough horizontal plane. A force of 2020 N is applied at 30∘30^\circ above the horizontal and the particle stays at rest. Find
    (a) the normal reaction and (b) the friction force, to 3 s.f. (g=9.8g = 9.8.)
    Level 3 · 4 marksTry it
  3. 3
    A particle of mass 44 kg rests on a rough slope inclined at 25∘25^\circ and is on the point of sliding down. Find the coefficient of friction, to 3 s.f.
    Level 3 · 2 marksTry it
  4. 4
    A particle of weight 4040 N hangs in equilibrium from two light strings making 30∘30^\circ and 60∘60^\circ with the horizontal, on opposite sides. Find the tensions T1T_1 (in the 30∘30^\circ string) and T2T_2 (in the 60∘60^\circ string), to 3 s.f.
    Level 3 · 3 marksTry it
  5. 5
    A particle of mass 22 kg rests on a rough slope of 20∘20^\circ with coefficient of friction 0.30.3. Find the least force, applied up the slope, needed to stop it sliding down, to 3 s.f. (g=9.8g = 9.8.)
    Level 3 · 2 marksTry it

12 more questions on statics — equilibrium under several forces

Free with an account — just an email, no card. The whole bank, every mark scheme and worked solution.

Start free