A-level · Exponentials & logarithms

Exponential growth and decay modelsExam-style questions

Real-world models of the form N = N0 e^{kt} (or A = a + b e^{kt}): finding the starting value, fitting the rate constant to data with logs, interpreting parameters, rates and limiting values.

26 questions · A-level level · mark scheme and worked solution on each · no sign-up to try

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  1. 1
    tSFigure 1

    A company launches a new sports drink. The weekly sales of the drink, SS thousand bottles, are modelled by the equation

    S=40+90e−0.2t−110e−0.5tS = 40 + 90\mathrm{e}^{-0.2t} - 110\mathrm{e}^{-0.5t}

    where tt is the number of weeks after the launch.

    Figure 1 shows a sketch of the graph of SS against tt.

    Use the equation of the model to answer parts (a) to (e).
    (a) Find the weekly sales of the drink at the time of the launch.

    (1 mark)
    (b) Write down the value that the weekly sales approach as tt becomes large.

    (1 mark)
    (c) Using calculus, find the value of tt at which the weekly sales are greatest, giving your answer to 3 decimal places.

    (Solutions relying entirely on calculator technology are not acceptable.)

    (5 marks)

    The weekly sales fall to 5050 thousand bottles for the second time when t=Mt = M
    (d) Show that MM is a root of the equation

    t=5ln⁡(91+11e−0.5t)t = 5\ln\left(\frac{9}{1 + 11\mathrm{e}^{-0.5t}}\right)

    (2 marks)
    (e) (i) Starting with t1=11t_1 = 11, use the iteration formula

    tn+1=5ln⁡(91+11e−0.5tn)t_{n+1} = 5\ln\left(\frac{9}{1 + 11\mathrm{e}^{-0.5t_n}}\right)

    to find the value of t2t_2, giving your answer to 4 decimal places.

    (ii) Continue the iteration to find the value of MM, giving your answer to 4 decimal places.

    (3 marks)
    Level 5 · 12 marksTry it
  2. 2
    A patient is given two drugs, X and Y, at the same time. The amount of each drug in the patient's body then decreases exponentially.

    The amount of drug X in the patient's body, MM mg, tt hours after it is given, is modelled by M=480e−0.2tM = 480e^{-0.2t}.
    (a) Find how long it takes for the amount of drug X in the patient's body to halve.

    (3 marks)

    Immediately after it is given, the amount of drug Y in the patient's body is 500500 mg. Three hours later it is 200200 mg.
    (b) Find how long after the drugs are given the amounts of X and Y in the patient's body are decreasing at the same rate.

    (8 marks)
    Level 5 · 11 marksTry it
  3. 3
    A population is modelled by P=5000e0.08tP = 5000 e^{0.08t}, where tt is the time in years.
    (a) State the initial population. (1 mark)
    (b) Find the population after 1010 years, to the nearest hundred. (2 marks)
    (c) Find, to 3 s.f., the time for the population to reach 1200012000. (3 marks)
    (d) Find dPdt\dfrac{\mathrm{d}P}{\mathrm{d}t} when t=10t = 10 and interpret it. (3 marks)
    Level 5 · 9 marksTry it
  4. 4
    The temperature θ ∘\theta\,^\circC of a cooling drink is modelled by θ=20+60e−0.05t\theta = 20 + 60 e^{-0.05t}, where tt is the time in minutes.
    (a) State the initial temperature. (1 mark)
    (b) Find the temperature after 1515 minutes, to 1 d.p. (2 marks)
    (c) Find the time for the temperature to fall to 40 ∘40\,^\circC, to 3 s.f. (3 marks)
    (d) State the temperature the drink approaches in the long term, and why. (2 marks)
    Level 5 · 8 marksTry it
  5. 5
    A quantity NN is modelled by N=N0ektN = N_0 e^{kt}. When t=0t = 0, N=200N = 200; when t=5t = 5, N=500N = 500.
    (a) Write down the value of N0N_0. (1 mark)
    (b) Show that k=15ln⁡2.5k = \tfrac15\ln 2.5. (3 marks)
    (c) Find the value of NN when t=8t = 8, to the nearest whole number. (3 marks)
    Level 5 · 7 marksTry it

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