A-level · Differentiation

Tangents and normalsExam-style questions

The straight lines that touch a curve, and the ones at right angles to it. Where a tangent's point and gradient come from; writing its equation in the form asked for; the normal and why its gradient is the negative reciprocal; finding the point where a tangent has a given gradient; where tangents and normals meet the axes; and where a tangent meets the curve again.

15 questions · A-level level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 2Level 3Level 4Level 5
  1. 1
    OxyA function is defined by f(x)=x2+2x\mathrm{f}(x) = x^{2} + \dfrac{2}{x} for x≠0x \neq 0. The graph of y=f(x)y = \mathrm{f}(x) is shown in the diagram.
    (a) Find the set of values of xx for which f(x)\mathrm{f}(x) is decreasing.

    (5 marks)
    (b) The tangent to the curve at the point PP, where x=2x = 2, and the normal to the curve at PP form a triangle with the xx-axis.

    Find the area of this triangle. Give your answer correct to 3 significant figures.

    (8 marks)
    Level 5 · 13 marksTry it
  2. 2
    In this question you must show all stages of your working.

    Solutions relying entirely on calculator technology are not acceptable.

    A curve has equation y=f(x)y = \text{f}(x), x>0x > 0, where

    f′(x)=6x+kx−22\text{f}'(x) = 6\sqrt{x} + \dfrac{k}{\sqrt{x}} - 22

    and kk is a constant.

    The tangent to the curve at the point P(16,70)P(16, 70) is parallel to the line with equation 12x−2y+7=012x - 2y + 7 = 0
    (a) (i) Show that k=16k = 16

    (ii) Find an equation of the tangent to the curve at PP, giving your answer in the form y=mx+cy = mx + c

    (4 marks)
    (b) Hence find the value of f′′(16)\text{f}''(16).

    (3 marks)
    (c) Find f(x)\text{f}(x).

    (4 marks)
    Level 5 · 11 marksTry it
  3. 3
    In this question you must show all stages of your working.

    Solutions relying entirely on calculator technology are not acceptable.

    The curve CC has equation y=f(x)y = \text{f}(x), x>0x > 0, where

    f′(x)=ax2+bx−18xx\text{f}'(x) = \dfrac{ax^2 + bx - 18}{x\sqrt{x}}

    and aa and bb are constants.

    The point P(9,66)P(9, 66) lies on CC and the gradient of CC at PP is 88
    (a) Show that 9a+b=269a + b = 26

    (2 marks)

    Given also that a+b=2a + b = 2
    (b) find f(x)\text{f}(x), giving each term in simplest form.

    (7 marks)
    (c) State the coordinates of the image of PP on the curve with equation y=f(x+6)y = \text{f}(x + 6).

    (1 mark)
    Level 5 · 10 marksTry it
  4. 4
    In this question you must show all stages of your working.

    Solutions relying entirely on calculator technology are not acceptable.

    The curve CC, with equation y=f(x)y = \text{f}(x), x>0x > 0, passes through the point P(9,−30)P(9, -30) and has gradient function

    f′(x)=(x+3)(2x−5)\text{f}'(x) = (\sqrt{x} + 3)(2\sqrt{x} - 5)
    (a) (i) Show that the gradient of CC at PP is 66

    (ii) Hence find an equation of the normal to CC at PP, writing it in the form ax+by+c=0ax + by + c = 0, where aa, bb and cc are integers.

    (4 marks)
    (b) Find f(x)\text{f}(x).

    (6 marks)
    Level 5 · 10 marksTry it