A-level · Differentiation

Differentiation from first principlesExam-style questions

The definition every differentiation rule is built on. What "the gradient at a point" means, as the limit of chords; the definition f'(x) as a limit; writing out f(x + h) correctly; cancelling h before letting it shrink; setting out the proof the way the marks are given; and finding the gradient at one point from first principles.

8 questions · A-level level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 2Level 3Level 4Level 5
  1. 1
    Given that

    y=5x2−3xy = 5x^2 - 3x

    use differentiation from first principles to show that

    dydx=10x−3\frac{dy}{dx} = 10x - 3

    (3 marks)
    Level 2 · 3 marksTry it
  2. 2
    A curve has equation y=f(x)y = \mathrm{f}(x), where f(x)=2x+16x\mathrm{f}(x) = 2\sqrt{x} + \dfrac{16}{x} for x>0x > 0. The points P(4, 8)P(4,\ 8), Q(3.999, k)Q(3.999,\ k), R(3.99, 8.00502)R(3.99,\ 8.00502), S(3.9, 8.05225)S(3.9,\ 8.05225) and T(3, 8.79743)T(3,\ 8.79743) lie on the curve. Values that are not exact are given correct to 5 decimal places.
    (a) Find the value of kk. Give your answer correct to 5 decimal places.

    (1 mark)
    (b) The table shows the gradients of the chords PTPT, PSPS, PRPR and PQPQ, correct to 4 decimal places.
    ChordPTPTPSPSPRPRPQPQ
    Gradient of chord−0.7974-0.7974−0.5022-0.5022−0.5002-0.5002
    Find the gradient of the chord PSPS. Give your answer correct to 4 decimal places.

    (1 mark)
    (c) State what the values in the table indicate about the value of f′(4)\mathrm{f}'(4).

    (1 mark)
    Level 2 · 3 marksTry it
  3. 3
    Given that

    f(x)=2x3−5xf(x) = 2x^3 - 5x,

    use differentiation from first principles to show that f′(x)=6x2−5f'(x) = 6x^2 - 5. (4 marks)
    Level 3 · 4 marksTry it
  4. 4
    Differentiate sin⁡x\sin x with respect to xx from first principles.

    (4 marks)
    Level 3 · 4 marksTry it
  5. 5
    Prove, from first principles, that the derivative of sin⁡x\sin x is cos⁡x\cos x.

    You may assume the addition formula for sin⁡(A+B)\sin(A + B) and the small-angle limits sin⁡hh→1\dfrac{\sin h}{h} \to 1 and cos⁡h−1h→0\dfrac{\cos h - 1}{h} \to 0 as h→0h \to 0. (5 marks)
    Level 3 · 5 marksTry it

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