A-level · Differentiation

Connected rates of changeExam-style questions

Working out how fast one quantity changes from how fast another does. Why linked quantities have linked rates; the chain rule as the bridge, dV/dt = (dV/dh)(dh/dt); finding the formula that links them in one variable; differentiating before substituting; signs and units for quantities that shrink; and chains of three rates, including a point moving along a curve.

22 questions · A-level level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 2Level 3Level 4
  1. 1
    Water drains from an inverted cone whose height always equals its radius, so V=13πr3V = \tfrac13\pi r^3, at 8 cm3s−18\text{ cm}^3\text{s}^{-1}. Find the rate at which the radius is decreasing when r=4 cmr = 4\text{ cm}.
    Level 3 · 3 marksTry it
  2. 2
    A cylindrical rainwater tank has a radius of 0.80.8 m and is being filled with water from a downpipe.

    In a model for the filling of the tank,
    • the walls of the tank are treated as having no thickness
    • the volume of water in the tank increases at a rate that is inversely proportional to the depth of the water
    The depth of the water in the tank is hh metres, tt minutes after the tank starts to fill.
    (a) Show that

    dhdt=λh\frac{dh}{dt} = \frac{\lambda}{h}

    where λ\lambda is a positive constant.

    (3 marks)

    When the depth of the water is 0.50.5 m, the depth is increasing at a rate of 0.040.04 m per minute.
    (b) Write down the value of λ\lambda.

    (1 mark)
    Level 3 · 4 marksTry it
  3. 3
    A spherical balloon is inflated at 100 cm3s−1100\text{ cm}^3\text{s}^{-1}. Show that its surface area S=4πr2S = 4\pi r^2 increases at 200r cm2s−1\dfrac{200}{r}\text{ cm}^2\text{s}^{-1}, and find this rate when r=5 cmr = 5\text{ cm}.
    Level 3 · 4 marksTry it
  4. 4
    A soap bubble is modelled as a sphere of radius rr cm. Air is blown into the bubble so that its volume, VV cm³, increases at a constant rate of kk cm³ s⁻¹, where kk is a positive constant.

    The surface area of the bubble is SS cm².

    Show that, according to the model, the rate at which SS is increasing is inversely proportional to rr.

    [The volume VV and the surface area SS of a sphere of radius rr are given by V=43πr3V = \dfrac{4}{3}\pi r^3 and S=4πr2S = 4\pi r^2]

    (4 marks)
    Level 3 · 4 marksTry it
  5. 5
    Air is pumped into a spherical balloon at 50 cm3s−150\text{ cm}^3\text{s}^{-1}. Find the rate at which the radius is increasing when r=5 cmr = 5\text{ cm}. (V=43πr3)\left(V = \tfrac43\pi r^3\right)
    Level 3 · 3 marksTry it

7 more questions on connected rates of change

Free with an account — just an email, no card. The whole bank, every mark scheme and worked solution.

Start free