A-level · Complex numbers

Complex roots of polynomial equationsExam-style questions

Solving quadratics with a negative discriminant to get a conjugate pair of complex roots; the theorem that complex roots of a real-coefficient polynomial come in conjugate pairs; using one known complex root to find the others and factorise cubics and quartics; and finding the square roots of a + bi by equating real and imaginary parts.

15 questions · A Level level · mark scheme and worked solution on each · no sign-up to try

DifficultyAllLevel 1Level 2Level 3Level 4Level 5
  1. 1
    The complex number 1+2i1 + 2i is a root of a polynomial equation that has real coefficients.
    (a) Write down another root of the equation. (1 mark)
    (b) Hence find a quadratic factor of the polynomial that has real coefficients. (2 marks)
    Level 3 · 3 marksTry it
  2. 2
    (a) Solve the equation z2+4z+29=0z^{2} + 4z + 29 = 0, giving your answers in the form a+bia + bi. (3 marks)
    (b) Verify that the product of your roots equals the constant term. (1 mark)
    Level 3 · 4 marksTry it
  3. 3
    Find a quadratic equation with real coefficients that has 4+i4 + i as a root, giving your answer in the form z2+bz+c=0z^{2} + bz + c = 0. (3 marks)
    Level 3 · 3 marksTry it
  4. 4
    Solve the equation (z−1)2=−9(z - 1)^{2} = -9, giving your answers in the form a+bia + bi. (3 marks)
    Level 3 · 3 marksTry it