igureMaths
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Level 5
Prime factorisation
17 questions
Lesson
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360
=
2
3
×
3
2
×
5
360 = 2^3 \times 3^2 \times 5
360
=
2
3
×
3
2
×
5
Find the smallest whole number that 360 must be multiplied by to give a cube number.
●●●●●
Level 5
3 marks
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N
=
2
3
×
5
2
N = 2^3 \times 5^2
N
=
2
3
×
5
2
(a)
Write down the value of
N
N
N
.
(b)
Work out how many factors
N
N
N
has in total.
Hint: every factor of
N
N
N
has the form
2
a
×
5
b
2^a \times 5^b
2
a
×
5
b
.
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Level 5
3 marks
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HCF and LCM
17 questions
Lesson
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Two whole numbers are each greater than 6.
The highest common factor of the two numbers is 6.
The lowest common multiple of the two numbers is 90.
Find the two numbers.
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Level 5
3 marks
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The highest common factor of two numbers is
4
4
4
.
The lowest common multiple of the same two numbers is
48
48
48
.
One of the numbers is
12
12
12
.
Find the other number.
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Level 5
3 marks
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