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Number · Surds

Chapter 1 · 4

The idea

Expanding brackets with surds

Why surds multiply out exactly like algebra — with √a·√a collapsing to a — how squares like (4 − √2)² keep their middle term, and why conjugate pairs multiply to a whole number.

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Number · Surds

Expanding brackets with surds

Why surds multiply out exactly like algebra — with √a·√a collapsing to a — how squares like (4 − √2)² keep their middle term, and why conjugate pairs multiply to a whole number.

Why it works

Treat √3 like x — with one collapse

Brackets with surds expand by exactly the rules you already know from algebra — treat 3\sqrt{3} the way you'd treat xx. The only new move is that a×a\sqrt{a} \times \sqrt{a} collapses to aa, so surd expansions simplify after expanding in a way algebra can't.

Single brackets

3(4+3)=43+33=43+3\sqrt{3}(4 + \sqrt{3}) = 4\sqrt{3} + \sqrt{3}\sqrt{3} = 4\sqrt{3} + 3. Multiply through, collapse any aa\sqrt{a}\sqrt{a}, collect. When multiplying mixed terms, coefficients multiply with coefficients and roots with roots: 23×57=(2×5)3×7=10212\sqrt{3} \times 5\sqrt{7} = (2\times5)\sqrt{3 \times 7} = 10\sqrt{21}.

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The rest of the explanation, plus 2 worked examples you step through move by move.

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