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Mechanics · Forces & Newton's laws

Chapter 1 · 4

The idea

Forces on an inclined plane

Resolving the weight on a slope into components along (mg sinα) and perpendicular (mg cosα) to the surface, the normal reaction R = mg cosα, and applying F = ma along the slope (acceleration g sinα on a smooth slope).

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Mechanics · Forces & Newton's laws

Forces on an inclined plane

Resolving the weight on a slope into components along (mg sinα) and perpendicular (mg cosα) to the surface, the normal reaction R = mg cosα, and applying F = ma along the slope (acceleration g sinα on a smooth slope).

Why it works

Resolve along and into the slope

When a body sits or slides on a slope, gravity still pulls it straight down — but the motion is along the slope, so resolving horizontally and vertically is clumsy. The clean choice is to resolve along and perpendicular to the slope instead.

The weight splits in two

For a slope at angle α\alpha to the horizontal, the weight mgmg splits into two components:

down the slope: mgsin⁡α,into the slope: mgcos⁡α\text{down the slope: } mg\sin\alpha, \qquad \text{into the slope: } mg\cos\alpha

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