Leave lesson

Pure · Trigonometry

Chapter 1 · 3

The idea

The sec/cosec/cot identities

The two new Pythagorean identities 1 + tan²θ ≡ sec²θ and 1 + cot²θ ≡ cosec²θ — deriving them from sin²+cos²≡1, and using them to prove identities, simplify expressions and turn equations into a solvable quadratic.

A full journey — read it, play with it, work it, then earn real exam marks. Everything stays on the timeline below.

In this lesson — start anywhere

Pure · Trigonometry

The sec/cosec/cot identities

The two new Pythagorean identities 1 + tan²θ ≡ sec²θ and 1 + cot²θ ≡ cosec²θ — deriving them from sin²+cos²≡1, and using them to prove identities, simplify expressions and turn equations into a solvable quadratic.

Why it works

One identity you already own

Here is the problem this page solves. Exam questions now mix the new functions with the old ones — an equation like

2sec⁡2θ−3tan⁡θ−1=02\sec^2\theta - 3\tan\theta - 1 = 0

has a sec⁡\sec and a tan⁡\tan in it, and you can't solve for two different functions at once. You need a bridge between them. The good news: you already own the only identity that matters, sin⁡2θ+cos⁡2θ≡1\sin^2\theta + \cos^2\theta \equiv 1 — and both bridges on this page are just that identity in disguise.

Keep reading — free

The rest of the explanation, plus 3 worked examples you step through move by move.

Start free

Takes a minute — no card.