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Mechanics · Kinematics

Chapter 1 · 3

The idea

Vertical motion under gravity

Why an object moving freely under gravity is just a constant-acceleration problem with a = ±g, how to choose a positive direction and translate "thrown up", "returns", "hits the ground" into suvat values, and why the up-and-down trip makes distance and displacement differ.

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Mechanics · Kinematics

Vertical motion under gravity

Why an object moving freely under gravity is just a constant-acceleration problem with a = ±g, how to choose a positive direction and translate "thrown up", "returns", "hits the ground" into suvat values, and why the up-and-down trip makes distance and displacement differ.

Why it works

Suvat with a = ±g

"Moving freely under gravity" is a modelling phrase with a precise meaning: the only force acting is gravity. That makes the acceleration constant — its size is g≈9.8 m s−2g \approx 9.8\ \text{m s}^{-2} (some questions tell you to use 10 m s−210\ \text{m s}^{-2}), always directed downwards. Constant acceleration means the whole toolkit you already have applies: vertical motion under gravity is just suvat with a=±ga = \pm g. Nothing new — except discipline with signs.

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The rest of the explanation, plus 3 worked examples you step through move by move.

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