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Geometry & measures · Trigonometry (sine & cosine rules)

Chapter 1 · 3

The idea

Area of a triangle & 3D trigonometry

Why ½ab sin C works for any triangle, using it in reverse to find an angle, and the method for 3D problems — find the right-angled triangle inside the solid, then work in two dimensions.

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Geometry & measures · Trigonometry (sine & cosine rules)

Area of a triangle & 3D trigonometry

Why ½ab sin C works for any triangle, using it in reverse to find an angle, and the method for 3D problems — find the right-angled triangle inside the solid, then work in two dimensions.

Why it works

The familiar area formula in disguise

This lesson holds the last two tricks of GCSE trigonometry: an area formula that needs no height, and the move that turns a frightening 3D solid into an ordinary flat triangle. First the area. You know Area=12×base×perpendicular height\text{Area} = \frac{1}{2} \times \text{base} \times \text{perpendicular height} — and 12absin⁡C\frac{1}{2}ab\sin C is that same formula in disguise. Take bb as the base; the height from the far vertex is asin⁡Ca\sin C, because the side aa leans away from the base at angle CC. So

Area=12absin⁡C.\text{Area} = \tfrac{1}{2}ab\sin C.

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The rest of the explanation, plus 2 worked examples you step through move by move.

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