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Algebra · Simultaneous equations

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Substitution and real-world simultaneous equations

Why substitution collapses two equations into one, the bracket that guards every substitution, and how to translate two-fact word problems (prices, sums, perimeters, intersections) into a solvable pair.

Algebra · Simultaneous equations

Substitution and real-world simultaneous equations

Why substitution collapses two equations into one, the bracket that guards every substitution, and how to translate two-fact word problems (prices, sums, perimeters, intersections) into a solvable pair.

Why it works

Substitution trades one unknown for the other. If one equation already isolates a variable — y=2x3y = 2x - 3 — then wherever the other equation says yy, you may write (2x3)(2x - 3) instead:

x+y=9        x+(2x3)=9    3x=12    x=4,  y=5.x + y = 9 \;\;\to\;\; x + (2x - 3) = 9 \;\Rightarrow\; 3x = 12 \;\Rightarrow\; x = 4,\; y = 5.

Two equations became one equation in one unknown — the familiar kind. Substitution shines exactly when a formula-form equation (y=y = \ldots) is already on the table; elimination shines when both equations are in ax+by=cax + by = c shape.

The bracket is non-negotiable. Substituting y=3x+1y = 3x + 1 into 2x+3y=252x + 3y = 25 gives 2x+3(3x+1)=252x + 3(3x + 1) = 25 — the 3 multiplies the WHOLE of yy. Dropping the bracket (2x+3×3x+12x + 3 \times 3x + 1) silently loses the +3+3 and wrecks everything after. And always substitute into the OTHER equation — feeding y=2x3y = 2x - 3 back into itself just proves 0=00 = 0.

Word problems: two facts, two equations. Let the letters be NUMBERS (costs, ages, lengths — with units), then translate each sentence:
  • "3 adult and 2 child tickets cost £24.30"3a+2c=24.303a + 2c = 24.30
  • "2 adult and 3 child tickets cost £21.20"2a+3c=21.202a + 3c = 21.20
Solve (eliminate or substitute) and answer in context: adult £6.10, child £3.00. Sum-and-difference problems are the same game: "sum 41, difference 9" is x+y=41x + y = 41, xy=9x - y = 9 — add to get 2x=502x = 50.

An intersection of two lines IS a simultaneous solution. The lines y=3x5y = 3x - 5 and y=x+7y = x + 7 cross where both equations hold at once: 3x5=x+73x - 5 = x + 7, so x=6x = 6, y=13y = 13 — the point (6,13)(6, 13). This is the picture behind every pair of simultaneous equations: two lines, one crossing point.

Sense-check the context. Prices come out in sensible money, lengths positive, ages human. A camel-sized ticket price means a slip upstream — recheck the subtraction, not the world.