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Probability · Combined events & tree diagrams

Chapter 1 · 4

The idea

Probability without replacement

Why the second pick happens in a smaller, changed bag — so the total always drops by one but a colour's count drops only if that colour was taken — and how that turns "one of each", "at least one" and the reverse quadratic questions.

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Probability · Combined events & tree diagrams

Probability without replacement

Why the second pick happens in a smaller, changed bag — so the total always drops by one but a colour's count drops only if that colour was taken — and how that turns "one of each", "at least one" and the reverse quadratic questions.

Why it works

One sentence, two consequences

Without replacement means the first thing you take is not put back before you take the second. That one sentence is the whole topic — but it has two consequences, and almost everybody remembers only one of them. Work with a real bag throughout: 5 red counters and 3 blue, 88 in total, two taken one after the other.

Multiply along a path — it's just counting

Think of the two picks as an ordered pair. There are 88 counters you could take first and, whichever one it was, 77 left to take second: 8×7=568 \times 7 = 56 equally likely pairs. Red-then-red pairs: 55 reds to take first, then 44 reds still in the bag, so 5×4=205 \times 4 = 20. Hence

P(both red)=5×48×7=2056=58×47.P(\text{both red}) = \frac{5 \times 4}{8 \times 7} = \frac{20}{56} = \frac{5}{8} \times \frac{4}{7}.

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